Resolves to std::is_assignable_v<t>.
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#include <seqan3/utility/concept/exposition_only/core_language.hpp>
Resolves to std::is_assignable_v<t>.
- Note
- This requires less than std::assignable_from, it simply tests if the expression
std::declval<T>() = std::declval<U>()
is well-formed.
- See also
- https://en.cppreference.com/w/cpp/types/is_assignable
This entity is not part of the SeqAn API. Do not rely on it in your applications.
The documentation for this interface was generated from the following file: